$$\int\frac{9}{5}\times(\frac{-3}{12})+\zeta\frac{9}{5}+\frac{5}{12})$$
$\frac{25-15С+108\zeta -27x}{60}$
$$\frac{-15\int \frac{9}{5}\mathrm{d}x+108\zeta +25}{60}$$
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$\frac{9\zeta }{5}-\frac{С}{4}-\frac{9x}{20}+\frac{5}{12}$
