Use Product Rule: \({x}^{a}{x}^{b}={x}^{a+b}\).
\[{\imath }^{2}ntx+\cos{y}=1\]
Use Square Rule: \({i}^{2}=-1\).
\[-1\times ntx+\cos{y}=1\]
Simplify \(-1\times ntx\) to \(-ntx\).
\[-ntx+\cos{y}=1\]
Subtract \(\cos{y}\) from both sides.
\[-ntx=1-\cos{y}\]
Divide both sides by \(-n\).
\[tx=-\frac{1-\cos{y}}{n}\]
Divide both sides by \(t\).
\[x=-\frac{\frac{1-\cos{y}}{n}}{t}\]
Simplify \(\frac{\frac{1-\cos{y}}{n}}{t}\) to \(\frac{1-\cos{y}}{nt}\).
\[x=-\frac{1-\cos{y}}{nt}\]
x=-(1-cos(y))/(n*t)
