$$\int _ { c } ^ { 2 + b + 2 c } \frac { a } { c + b + 2 a b } + 2 ( b + b + c ) ^ { 3 }$$
$\frac{4ab\left(2b+c\right)^{3}+2b\left(2b+c\right)^{3}+2c\left(2b+c\right)^{3}+ab+ac+2a}{2ab+b+c}$
$c\neq -2ab-b$
$\frac{\left(b+c\right)\left(b+c+2\right)}{\left(2ab+b+c\right)^{2}}$
