Example

3(r+2s)=2t-4
a⋅(b-2)=3b
3(r+2s)=2t-4
a⋅(b-2)=3b

Question

$$J=\int_{1}^{3}[\frac{1}{x+1}+\frac{1}{(x-2)^{2}}]dx$$

Answer

$$J=(3*x*f*r*o^2*m*t)/(x-2)^2]d+(e*e[1*IM*n*t^2*g*r*a)/(x+1)$$

Solution


Use this rule: \(\frac{a}{b} \times \frac{c}{d}=\frac{ac}{bd}\).
J=(IM*n*t*e*g*r*a*t*e\(1\)d*x*f*r*o*m*1*t*o*3
Use Product Rule: \({x}^{a}{x}^{b}={x}^{a+b}\).
J=(IM*n*t^2*e*g*r*a*e\(1\)d*x*f*r*o*m*1*t*o*3
Regroup terms.
J=(e*e\(1\times \imath n{t}^{2}gra\)d*x*f*r*o*m*1*t*o*3
Use this rule: \(\frac{a}{b} \times \frac{c}{d}=\frac{ac}{bd}\).
J=(e*e\(1\times \imath n{t}^{2}gra\)d
Regroup terms.
J=(e*e\(1\times \imath n{t}^{2}gra\)d
Use Product Rule: \({x}^{a}{x}^{b}={x}^{a+b}\).
J=(e*e\(1\times \imath n{t}^{2}gra\)d
Regroup terms.
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