Question

$$\left. \begin{array} { l } { 1 , 10 ^ { \circ } } \\ { 2 , 5 + 7 i } \end{array} \right.$$

Answer

$$-10*e^4*IM*t^3*h*m*u*l^2*p*c*a*n*v*r*s*o*f-4*deg(25)*IM+71$$

Solution


Regroup terms.
\[10ttthmullpcanvrsofe\imath \imath e\imath ee-4\imath 25^{\circ}+71\]
Simplify  \(10ttthmullpcanvrsofe\imath \imath e\imath ee\)  to  \(10{t}^{3}hmu{l}^{2}pcanvrsofe\imath \imath e\imath ee\).
\[10{t}^{3}hmu{l}^{2}pcanvrsofe\imath \imath e\imath ee-4\imath 25^{\circ}+71\]
Use Product Rule: \({x}^{a}{x}^{b}={x}^{a+b}\).
\[10{t}^{3}hmu{l}^{2}pcanvrsof{e}^{4}{\imath }^{3}-4\imath 25^{\circ}+71\]
Isolate \({\imath }^{2}\).
\[10{t}^{3}hmu{l}^{2}pcanvrsof{e}^{4}{\imath }^{2}\imath -4\imath 25^{\circ}+71\]
Use Square Rule: \({i}^{2}=-1\).
\[10{t}^{3}hmu{l}^{2}pcanvrsof{e}^{4}\times -1\times \imath -4\imath 25^{\circ}+71\]
Simplify  \(10{t}^{3}hmu{l}^{2}pcanvrsof{e}^{4}\times -1\times \imath \)  to  \(-10{t}^{3}hmu{l}^{2}pcanvrsof{e}^{4}\imath \).
\[-10{t}^{3}hmu{l}^{2}pcanvrsof{e}^{4}\imath -4\imath 25^{\circ}+71\]
Regroup terms.
\[-10{e}^{4}\imath {t}^{3}hmu{l}^{2}pcanvrsof-4\imath 25^{\circ}+71\]
Regroup terms.
\[-10{e}^{4}\imath {t}^{3}hmu{l}^{2}pcanvrsof-425^{\circ}\imath +71\]