Solve Simplify : ry : a ) 26 1 - 2/5 b ) ) 2 + 2/8; 4 - 12/29 8 e ) 2 f ) 25 | Equatix - Math Solver

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Example

3(r+2s)=2t-4

a⋅(b-2)=3b

3(r+2s)=2t-4

a⋅(b-2)=3b

Question

$$\left. \begin{array} { l } { 1 - \frac { 2 } { 5 } - 6 \quad 2 + \frac { 2 } { 8 } } \\ { 2 - \frac { 8 } { 25 } \quad 4 - \frac { 12 } { 29 } \quad } \end{array} \right.$$

Sort

$-\frac{1223}{20},\ \frac{222}{725}$

Solution Steps

Convert $1$ to fraction $\frac{5}{5}$.

$$sort(\frac{5}{5}-\frac{2}{5}-62+\frac{2}{8},2-\frac{8}{25}\times 4-\frac{12}{29})$$

Since $\frac{5}{5}$ and $\frac{2}{5}$ have the same denominator, subtract them by subtracting their numerators.

$$sort(\frac{5-2}{5}-62+\frac{2}{8},2-\frac{8}{25}\times 4-\frac{12}{29})$$

Subtract $2$ from $5$ to get $3$.

$$sort(\frac{3}{5}-62+\frac{2}{8},2-\frac{8}{25}\times 4-\frac{12}{29})$$

Convert $62$ to fraction $\frac{310}{5}$.

$$sort(\frac{3}{5}-\frac{310}{5}+\frac{2}{8},2-\frac{8}{25}\times 4-\frac{12}{29})$$

Since $\frac{3}{5}$ and $\frac{310}{5}$ have the same denominator, subtract them by subtracting their numerators.

$$sort(\frac{3-310}{5}+\frac{2}{8},2-\frac{8}{25}\times 4-\frac{12}{29})$$

Subtract $310$ from $3$ to get $-307$.

$$sort(-\frac{307}{5}+\frac{2}{8},2-\frac{8}{25}\times 4-\frac{12}{29})$$

Reduce the fraction $\frac{2}{8}$ to lowest terms by extracting and canceling out $2$.

$$sort(-\frac{307}{5}+\frac{1}{4},2-\frac{8}{25}\times 4-\frac{12}{29})$$

Least common multiple of $5$ and $4$ is $20$. Convert $-\frac{307}{5}$ and $\frac{1}{4}$ to fractions with denominator $20$.

$$sort(-\frac{1228}{20}+\frac{5}{20},2-\frac{8}{25}\times 4-\frac{12}{29})$$

Since $-\frac{1228}{20}$ and $\frac{5}{20}$ have the same denominator, add them by adding their numerators.

$$sort(\frac{-1228+5}{20},2-\frac{8}{25}\times 4-\frac{12}{29})$$

Add $-1228$ and $5$ to get $-1223$.

$$sort(-\frac{1223}{20},2-\frac{8}{25}\times 4-\frac{12}{29})$$

Express $\frac{8}{25}\times 4$ as a single fraction.

$$sort(-\frac{1223}{20},2-\frac{8\times 4}{25}-\frac{12}{29})$$

Multiply $8$ and $4$ to get $32$.

$$sort(-\frac{1223}{20},2-\frac{32}{25}-\frac{12}{29})$$

Convert $2$ to fraction $\frac{50}{25}$.

$$sort(-\frac{1223}{20},\frac{50}{25}-\frac{32}{25}-\frac{12}{29})$$

Since $\frac{50}{25}$ and $\frac{32}{25}$ have the same denominator, subtract them by subtracting their numerators.

$$sort(-\frac{1223}{20},\frac{50-32}{25}-\frac{12}{29})$$

Subtract $32$ from $50$ to get $18$.

$$sort(-\frac{1223}{20},\frac{18}{25}-\frac{12}{29})$$

Least common multiple of $25$ and $29$ is $725$. Convert $\frac{18}{25}$ and $\frac{12}{29}$ to fractions with denominator $725$.

$$sort(-\frac{1223}{20},\frac{522}{725}-\frac{300}{725})$$

Since $\frac{522}{725}$ and $\frac{300}{725}$ have the same denominator, subtract them by subtracting their numerators.

$$sort(-\frac{1223}{20},\frac{522-300}{725})$$

Subtract $300$ from $522$ to get $222$.

$$sort(-\frac{1223}{20},\frac{222}{725})$$

Least common denominator of the numbers in the list $-\frac{1223}{20},\frac{222}{725}$ is $2900$. Convert numbers in the list to fractions with denominator $2900$.

$$-\frac{177335}{2900},\frac{888}{2900}$$

Evaluate

$-\frac{1223}{20},\ \frac{222}{725}$