Example

3(r+2s)=2t-4
a⋅(b-2)=3b
3(r+2s)=2t-4
a⋅(b-2)=3b

Question

$$\left. \begin{array} { l } { 1 - ( + 2 ) \times ( - 12 ) = } \end{array} \right.$$

Answer

$$24*e^2*p*r^2*f*o*m*t*h*n*d$$

Solution


Take out the constants.
\[(2\times -12)prrfomthndee\imath \imath \]
Simplify  \(2\times -12\)  to  \(-24\).
\[-24prrfomthndee\imath \imath \]
Use Product Rule: \({x}^{a}{x}^{b}={x}^{a+b}\).
\[-24p{r}^{2}fomthnd{e}^{2}{\imath }^{2}\]
Use Square Rule: \({i}^{2}=-1\).
\[-24p{r}^{2}fomthnd{e}^{2}\times -1\]
Simplify  \(24p{r}^{2}fomthnd{e}^{2}\times -1\)  to  \(-24p{r}^{2}fomthnd{e}^{2}\).
\[-(-24p{r}^{2}fomthnd{e}^{2})\]
Regroup terms.
\[-(-24{e}^{2}p{r}^{2}fomthnd)\]
Remove parentheses.
\[24{e}^{2}p{r}^{2}fomthnd\]
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