Question

$$\left. \begin{array} { l } { 23 8 g = } \\ { 4 2 g = } \end{array} \right.$$

Answer

p=(14*(3*k*g+17))/(Ex*r*e*s*sin(k))

Solution


Use Product Rule: \({x}^{a}{x}^{b}={x}^{a+b}\).
\[Expres(\sin{k})g-238g=k{g}^{2}\times 42\]
Regroup terms.
\[Expres(\sin{k})g-238g=42k{g}^{2}\]
Factor out the common term \(g\).
\[g(Expres\sin{k}-238)=42k{g}^{2}\]
Divide both sides by \(g\).
\[Expres\sin{k}-238=\frac{42k{g}^{2}}{g}\]
Use Quotient Rule: \(\frac{{x}^{a}}{{x}^{b}}={x}^{a-b}\).
\[Expres\sin{k}-238=42k{g}^{2-1}\]
Simplify  \(2-1\)  to  \(1\).
\[Expres\sin{k}-238=42k{g}^{1}\]
Use Rule of One: \({x}^{1}=x\).
\[Expres\sin{k}-238=42kg\]
Add \(238\) to both sides.
\[Expres\sin{k}=42kg+238\]
Factor out the common term \(14\).
\[Expres\sin{k}=14(3kg+17)\]
Divide both sides by \(Ex\).
\[pres\sin{k}=\frac{14(3kg+17)}{Ex}\]
Divide both sides by \(r\).
\[pes\sin{k}=\frac{\frac{14(3kg+17)}{Ex}}{r}\]
Simplify  \(\frac{\frac{14(3kg+17)}{Ex}}{r}\)  to  \(\frac{14(3kg+17)}{Exr}\).
\[pes\sin{k}=\frac{14(3kg+17)}{Exr}\]
Divide both sides by \(e\).
\[ps\sin{k}=\frac{\frac{14(3kg+17)}{Exr}}{e}\]
Simplify  \(\frac{\frac{14(3kg+17)}{Exr}}{e}\)  to  \(\frac{14(3kg+17)}{Exre}\).
\[ps\sin{k}=\frac{14(3kg+17)}{Exre}\]
Divide both sides by \(s\).
\[p\sin{k}=\frac{\frac{14(3kg+17)}{Exre}}{s}\]
Simplify  \(\frac{\frac{14(3kg+17)}{Exre}}{s}\)  to  \(\frac{14(3kg+17)}{Exres}\).
\[p\sin{k}=\frac{14(3kg+17)}{Exres}\]
Divide both sides by \(\sin{k}\).
\[p=\frac{\frac{14(3kg+17)}{Exres}}{\sin{k}}\]
Simplify  \(\frac{\frac{14(3kg+17)}{Exres}}{\sin{k}}\)  to  \(\frac{14(3kg+17)}{Exres\sin{k}}\).
\[p=\frac{14(3kg+17)}{Exres\sin{k}}\]