$$\left. \begin{array} { l } { 3 A + 58 + 2 x = 0 } \\ { A = 41 } \\ { 45 } \end{array} \right.$$
$a=45$
$$3\times 41+58+2x=0$$
$$123+58+2x=0$$
$$181+2x=0$$
$$2x=-181$$
$$x=-\frac{181}{2}$$
$$A=41$$ $$x=-\frac{181}{2}$$ $$a=45$$
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