Question

$$\left. \begin{array} { l } { 3 a ^ { 2 } - 2 a } \\ { + 5 \quad } \\ { a = } \end{array} \right.$$

Answer

$$3*Ev*e*a^4*l*u*t-2*a;5*IM*f*9$$

Solution


Regroup terms.
\[\begin{aligned}&3aa{a}^{2}lutEve-2a\\&5\imath f\times 9\end{aligned}\]
Use Product Rule: \({x}^{a}{x}^{b}={x}^{a+b}\).
\[\begin{aligned}&3{a}^{1+1+2}lutEve-2a\\&5\imath f\times 9\end{aligned}\]
Simplify  \(1+1\)  to  \(2\).
\[\begin{aligned}&3{a}^{2+2}lutEve-2a\\&5\imath f\times 9\end{aligned}\]
Simplify  \(2+2\)  to  \(4\).
\[\begin{aligned}&3{a}^{4}lutEve-2a\\&5\imath f\times 9\end{aligned}\]
Regroup terms.
\[\begin{aligned}&3Eve{a}^{4}lut-2a\\&5\imath f\times 9\end{aligned}\]