How to solve () 100 C above the freezing point (iv) 5 kg decrease in weight . () A gain of 25,000 At Shimla , temperature was -6 C on Monday and then it dropped by 2C on Tuesday What was the temperature of Shimla on Tuesday ? Next day it rose by 3C. What was Shimla's temperature on Wednesday?

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1. Factor the equation (x + 2)(x + 3) = 0. 2. Set each factor equal to zero: x + 2 = 0 and x + 3 = 0. 3. Solve for x: x = -2 and x = -3.

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