$$\left. \begin{array} { l } { 9 a ^ { 2 } b - b , 6 a ^ { 2 } + 2 a } \end{array} \right.$$
$18ba^{3}-2ab$
$$-b+9ba^{2}=b\left(3a-1\right)\left(3a+1\right)$$ $$6a^{2}+2a=2a\left(3a+1\right)$$
$$2ab\left(3a-1\right)\left(3a+1\right)$$
$$-2ab+18ba^{3}$$
Show Solution
Hide Solution
$b\left(9a^{2}-1\right),\ 2a\left(3a+1\right)$