$$\left. \begin{array} { l } { A = 4 + 2 \times ( 3 + 3 - 5 ) + 1 } \end{array} \right.$$
$A=7$
$$A=4+2\left(6-5\right)+1$$
$$A=4+2\times 1+1$$
$$A=4+2+1$$
$$A=6+1$$
$$A=7$$
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