$$\left. \begin{array} { l } { c ^ { 2 } - 2 u t } \\ { 4 x - 3 } \end{array} \right.$$
$\left(3-4x\right)\left(c^{2}-2tu\right)$
$$\left(3-4x\right)\left(c^{2}-2tu\right)$$
$$8tux-4xc^{2}-6tu+3c^{2}$$
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$c^{2}-2tu,\ 4x-3$
