Question

$$\left. \begin{array} { l } { = - 5 } \right.$$

Answer

$$l=(2412*tanX)/(5*e^2*het*heyfindt*heot*hertrignometric*s^2*t^2*h*10^(t*h))$$

Solution


Use Product Rule: \({x}^{a}{x}^{b}={x}^{a+b}\).
\[2412tanX=-5l{\imath }^{2}{e}^{2}{s}^{2}{t}^{2}h\times {10}^{th}hetheyfindtheothertrignometric\]
Use Square Rule: \({i}^{2}=-1\).
\[2412tanX=-5l\times -1\times {e}^{2}{s}^{2}{t}^{2}h\times {10}^{th}hetheyfindtheothertrignometric\]
Simplify  \(5l\times -1\times {e}^{2}{s}^{2}{t}^{2}h\times {10}^{th}hetheyfindtheothertrignometric\)  to  \(-5l{s}^{2}{t}^{2}h{e}^{2}\times {10}^{th}hetheyfindtheothertrignometric\).
\[2412tanX=-(-5l{s}^{2}{t}^{2}h{e}^{2}\times {10}^{th}hetheyfindtheothertrignometric)\]
Regroup terms.
\[2412tanX=-(-5{e}^{2}hetheyfindtheothertrignometricl{s}^{2}{t}^{2}h\times {10}^{th})\]
Remove parentheses.
\[2412tanX=5{e}^{2}hetheyfindtheothertrignometricl{s}^{2}{t}^{2}h\times {10}^{th}\]
Divide both sides by \(5\).
\[\frac{2412tanX}{5}={e}^{2}hetheyfindtheothertrignometricl{s}^{2}{t}^{2}h\times {10}^{th}\]
Divide both sides by \({e}^{2}\).
\[\frac{\frac{2412tanX}{5}}{{e}^{2}}=hetheyfindtheothertrignometricl{s}^{2}{t}^{2}h\times {10}^{th}\]
Simplify  \(\frac{\frac{2412tanX}{5}}{{e}^{2}}\)  to  \(\frac{2412tanX}{5{e}^{2}}\).
\[\frac{2412tanX}{5{e}^{2}}=hetheyfindtheothertrignometricl{s}^{2}{t}^{2}h\times {10}^{th}\]
Divide both sides by \(het\).
\[\frac{\frac{2412tanX}{5{e}^{2}}}{het}=heyfindtheothertrignometricl{s}^{2}{t}^{2}h\times {10}^{th}\]
Simplify  \(\frac{\frac{2412tanX}{5{e}^{2}}}{het}\)  to  \(\frac{2412tanX}{5{e}^{2}het}\).
\[\frac{2412tanX}{5{e}^{2}het}=heyfindtheothertrignometricl{s}^{2}{t}^{2}h\times {10}^{th}\]
Divide both sides by \(heyfindt\).
\[\frac{\frac{2412tanX}{5{e}^{2}het}}{heyfindt}=heothertrignometricl{s}^{2}{t}^{2}h\times {10}^{th}\]
Simplify  \(\frac{\frac{2412tanX}{5{e}^{2}het}}{heyfindt}\)  to  \(\frac{2412tanX}{5{e}^{2}hetheyfindt}\).
\[\frac{2412tanX}{5{e}^{2}hetheyfindt}=heothertrignometricl{s}^{2}{t}^{2}h\times {10}^{th}\]
Divide both sides by \(heot\).
\[\frac{\frac{2412tanX}{5{e}^{2}hetheyfindt}}{heot}=hertrignometricl{s}^{2}{t}^{2}h\times {10}^{th}\]
Simplify  \(\frac{\frac{2412tanX}{5{e}^{2}hetheyfindt}}{heot}\)  to  \(\frac{2412tanX}{5{e}^{2}hetheyfindtheot}\).
\[\frac{2412tanX}{5{e}^{2}hetheyfindtheot}=hertrignometricl{s}^{2}{t}^{2}h\times {10}^{th}\]
Divide both sides by \(hertrignometric\).
\[\frac{\frac{2412tanX}{5{e}^{2}hetheyfindtheot}}{hertrignometric}=l{s}^{2}{t}^{2}h\times {10}^{th}\]
Simplify  \(\frac{\frac{2412tanX}{5{e}^{2}hetheyfindtheot}}{hertrignometric}\)  to  \(\frac{2412tanX}{5{e}^{2}hetheyfindtheothertrignometric}\).
\[\frac{2412tanX}{5{e}^{2}hetheyfindtheothertrignometric}=l{s}^{2}{t}^{2}h\times {10}^{th}\]
Divide both sides by \({s}^{2}\).
\[\frac{\frac{2412tanX}{5{e}^{2}hetheyfindtheothertrignometric}}{{s}^{2}}=l{t}^{2}h\times {10}^{th}\]
Simplify  \(\frac{\frac{2412tanX}{5{e}^{2}hetheyfindtheothertrignometric}}{{s}^{2}}\)  to  \(\frac{2412tanX}{5{e}^{2}hetheyfindtheothertrignometric{s}^{2}}\).
\[\frac{2412tanX}{5{e}^{2}hetheyfindtheothertrignometric{s}^{2}}=l{t}^{2}h\times {10}^{th}\]
Divide both sides by \({t}^{2}\).
\[\frac{\frac{2412tanX}{5{e}^{2}hetheyfindtheothertrignometric{s}^{2}}}{{t}^{2}}=lh\times {10}^{th}\]
Simplify  \(\frac{\frac{2412tanX}{5{e}^{2}hetheyfindtheothertrignometric{s}^{2}}}{{t}^{2}}\)  to  \(\frac{2412tanX}{5{e}^{2}hetheyfindtheothertrignometric{s}^{2}{t}^{2}}\).
\[\frac{2412tanX}{5{e}^{2}hetheyfindtheothertrignometric{s}^{2}{t}^{2}}=lh\times {10}^{th}\]
Divide both sides by \(h\).
\[\frac{\frac{2412tanX}{5{e}^{2}hetheyfindtheothertrignometric{s}^{2}{t}^{2}}}{h}=l\times {10}^{th}\]
Simplify  \(\frac{\frac{2412tanX}{5{e}^{2}hetheyfindtheothertrignometric{s}^{2}{t}^{2}}}{h}\)  to  \(\frac{2412tanX}{5{e}^{2}hetheyfindtheothertrignometric{s}^{2}{t}^{2}h}\).
\[\frac{2412tanX}{5{e}^{2}hetheyfindtheothertrignometric{s}^{2}{t}^{2}h}=l\times {10}^{th}\]
Divide both sides by \({10}^{th}\).
\[\frac{\frac{2412tanX}{5{e}^{2}hetheyfindtheothertrignometric{s}^{2}{t}^{2}h}}{{10}^{th}}=l\]
Simplify  \(\frac{\frac{2412tanX}{5{e}^{2}hetheyfindtheothertrignometric{s}^{2}{t}^{2}h}}{{10}^{th}}\)  to  \(\frac{2412tanX}{5{e}^{2}hetheyfindtheothertrignometric{s}^{2}{t}^{2}h\times {10}^{th}}\).
\[\frac{2412tanX}{5{e}^{2}hetheyfindtheothertrignometric{s}^{2}{t}^{2}h\times {10}^{th}}=l\]
Switch sides.
\[l=\frac{2412tanX}{5{e}^{2}hetheyfindtheothertrignometric{s}^{2}{t}^{2}h\times {10}^{th}}\]