$$\left. \begin{array} { l } { \frac { 3 \frac { 1 } { 12 } + \frac { 7 } { 8 } } { 2 \frac { 1 } { 4 } - \frac { 1 } { 6 } } } \end{array} \right.$$
$\frac{19}{10}=1.9$
$$\frac{\frac{36+1}{12}+\frac{7}{8}}{\frac{2\times 4+1}{4}-\frac{1}{6}}$$
$$\frac{\frac{37}{12}+\frac{7}{8}}{\frac{2\times 4+1}{4}-\frac{1}{6}}$$
$$\frac{\frac{74}{24}+\frac{21}{24}}{\frac{2\times 4+1}{4}-\frac{1}{6}}$$
$$\frac{\frac{74+21}{24}}{\frac{2\times 4+1}{4}-\frac{1}{6}}$$
$$\frac{\frac{95}{24}}{\frac{2\times 4+1}{4}-\frac{1}{6}}$$
$$\frac{\frac{95}{24}}{\frac{8+1}{4}-\frac{1}{6}}$$
$$\frac{\frac{95}{24}}{\frac{9}{4}-\frac{1}{6}}$$
$$\frac{\frac{95}{24}}{\frac{27}{12}-\frac{2}{12}}$$
$$\frac{\frac{95}{24}}{\frac{27-2}{12}}$$
$$\frac{\frac{95}{24}}{\frac{25}{12}}$$
$$\frac{95}{24}\times \frac{12}{25}$$
$$\frac{95\times 12}{24\times 25}$$
$$\frac{1140}{600}$$
$$\frac{19}{10}$$
Show Solution
Hide Solution
$\frac{19}{2 \cdot 5} = 1\frac{9}{10} = 1.9$