$$\left. \begin{array} { l } { \frac { 3 ^ { 100 } + 3 ^ { 101 } + 3 ^ { 102 } } { 3 ^ { 99 } + 3 ^ { 98 } - 3 ^ { 97 } } } \end{array} \right.$$
$\frac{351}{11}\approx 31.909090909$
$\frac{3 ^ {3} \cdot 13}{11} = 31\frac{10}{11} = 31.90909090909091$
