Question

$$\left. \begin{array} { l } { \frac { 7 ^ { 5 } \times 3 ^ { 4 } \times 7 } { 9 \times 49 ^ { 2 } } } \\ { [ ( 4 ) ^ { 5 } \times ( 4 ) ^ { 3 } ] ^ { 3 } ] } \end{array} \right.$$

Answer

$$He*r*e,441*Ex*e^2*sIn*p*r*t*h*d$$

Solution


Simplify  \({7}^{5}\)  to  \(16807\).
\[Here,ExpresInthed\times \frac{16807\times {3}^{4}\times 7}{9\times {49}^{2}}\]
Simplify  \({3}^{4}\)  to  \(81\).
\[Here,ExpresInthed\times \frac{16807\times 81\times 7}{9\times {49}^{2}}\]
Simplify  \(16807\times 81\)  to  \(1361367\).
\[Here,ExpresInthed\times \frac{1361367\times 7}{9\times {49}^{2}}\]
Simplify  \(1361367\times 7\)  to  \(9529569\).
\[Here,ExpresInthed\times \frac{9529569}{9\times {49}^{2}}\]
Simplify  \({49}^{2}\)  to  \(2401\).
\[Here,ExpresInthed\times \frac{9529569}{9\times 2401}\]
Simplify  \(9\times 2401\)  to  \(21609\).
\[Here,ExpresInthed\times \frac{9529569}{21609}\]
Simplify  \(\frac{9529569}{21609}\)  to  \(441\).
\[Here,ExpresInthed\times 441\]
Use Product Rule: \({x}^{a}{x}^{b}={x}^{a+b}\).
\[Here,Expr{e}^{2}sInthd\times 441\]
Regroup terms.
\[Here,441Ex{e}^{2}sInprthd\]