Question

$$\left. \begin{array} { l } { f ( x ) = 2 x ^ { 3 } - 3 x ^ { 2 } + 36 x } \end{array} \right.$$

Answer

$$o=(2*x^2-3*x+36)/(ORa*f^2)$$

Solution


Use Product Rule: \({x}^{a}{x}^{b}={x}^{a+b}\).
\[ORao{f}^{2}x=2{x}^{3}-3{x}^{2}+36x\]
Divide both sides by \(ORa\).
\[o{f}^{2}x=\frac{2{x}^{3}-3{x}^{2}+36x}{ORa}\]
Factor out the common term \(x\).
\[o{f}^{2}x=\frac{x(2{x}^{2}-3x+36)}{ORa}\]
Divide both sides by \({f}^{2}\).
\[ox=\frac{\frac{x(2{x}^{2}-3x+36)}{ORa}}{{f}^{2}}\]
Simplify  \(\frac{\frac{x(2{x}^{2}-3x+36)}{ORa}}{{f}^{2}}\)  to  \(\frac{x(2{x}^{2}-3x+36)}{ORa{f}^{2}}\).
\[ox=\frac{x(2{x}^{2}-3x+36)}{ORa{f}^{2}}\]
Divide both sides by \(x\).
\[o=\frac{\frac{x(2{x}^{2}-3x+36)}{ORa{f}^{2}}}{x}\]
Simplify  \(\frac{\frac{x(2{x}^{2}-3x+36)}{ORa{f}^{2}}}{x}\)  to  \(\frac{x(2{x}^{2}-3x+36)}{ORa{f}^{2}x}\).
\[o=\frac{x(2{x}^{2}-3x+36)}{ORa{f}^{2}x}\]
Cancel \(x\).
\[o=\frac{2{x}^{2}-3x+36}{ORa{f}^{2}}\]