Question

$$\left. \begin{array} { l } { f ( x ) = x - x ^ { 2 } ( - 1 , 1 ) } \end{array} \right.$$

Answer

$$r=(1+IM*x*n)/(8*e^2*IM*s^2),1/(8*e^2*IM*s^2*x)$$

Solution


Use Product Rule: \({x}^{a}{x}^{b}={x}^{a+b}\).
\[{s}^{2}{e}^{2}r\imath \times 8x=x-{x}^{2}\imath n(-1,1)\]
Regroup terms.
\[8{e}^{2}\imath {s}^{2}rx=x-{x}^{2}\imath n(-1,1)\]
Simplify  \({x}^{2}\imath n(-1,1)\)  to  \({x}^{2}\imath n\times -1,1\).
\[8{e}^{2}\imath {s}^{2}rx=x-({x}^{2}\imath n\times -1,1)\]
Simplify  \({x}^{2}\imath n\times -1\)  to  \(-{x}^{2}\imath n\).
\[8{e}^{2}\imath {s}^{2}rx=x-(-{x}^{2}\imath n,1)\]
Regroup terms.
\[8{e}^{2}\imath {s}^{2}rx=x-(-\imath {x}^{2}n,1)\]
Simplify  \(x-(-\imath {x}^{2}n,1)\)  to  \(x--\imath {x}^{2}n,1\).
\[8{e}^{2}\imath {s}^{2}rx=x+\imath {x}^{2}n,1\]
Break down the problem into these 2 equations.
\[8{e}^{2}\imath {s}^{2}rx=x+\imath {x}^{2}n\]
\[8{e}^{2}\imath {s}^{2}rx=1\]
Solve the 1st equation: \(8{e}^{2}\imath {s}^{2}rx=x+\imath {x}^{2}n\).
\[r=\frac{1+\imath xn}{8{e}^{2}\imath {s}^{2}}\]
Solve the 2nd equation: \(8{e}^{2}\imath {s}^{2}rx=1\).
\[r=\frac{1}{8{e}^{2}\imath {s}^{2}x}\]
Collect all solutions.
\[r=\frac{1+\imath xn}{8{e}^{2}\imath {s}^{2}},\frac{1}{8{e}^{2}\imath {s}^{2}x}\]