Question

$$\left. \begin{array} { l } { - 999.90.99.09.09 , \frac { 99.99.99 } { 10 } } \end{array} \right.$$

Answer

$$-999-2*Arranget*e^3*IM*h*f*o^2*l^2*w*n^4*g^2*d^2*s,81,-207,100$$

Solution


Regroup terms.
\[2hfoollwnnnnggddsArrangete\imath \imath ee\imath -999,90-9,-99-09-99,100\]
Simplify  \(2hfoollwnnnnggddsArrangete\imath \imath ee\imath \)  to  \(2hf{o}^{2}{l}^{2}w{n}^{4}{g}^{2}{d}^{2}sArrangete\imath \imath ee\imath \).
\[2hf{o}^{2}{l}^{2}w{n}^{4}{g}^{2}{d}^{2}sArrangete\imath \imath ee\imath -999,90-9,-99-09-99,100\]
Use Product Rule: \({x}^{a}{x}^{b}={x}^{a+b}\).
\[2hf{o}^{2}{l}^{2}w{n}^{4}{g}^{2}{d}^{2}sArranget{e}^{3}{\imath }^{3}-999,90-9,-99-09-99,100\]
Isolate \({\imath }^{2}\).
\[2hf{o}^{2}{l}^{2}w{n}^{4}{g}^{2}{d}^{2}sArranget{e}^{3}{\imath }^{2}\imath -999,90-9,-99-09-99,100\]
Use Square Rule: \({i}^{2}=-1\).
\[2hf{o}^{2}{l}^{2}w{n}^{4}{g}^{2}{d}^{2}sArranget{e}^{3}\times -1\times \imath -999,90-9,-99-09-99,100\]
Simplify  \(2hf{o}^{2}{l}^{2}w{n}^{4}{g}^{2}{d}^{2}sArranget{e}^{3}\times -1\times \imath \)  to  \(-2hf{o}^{2}{l}^{2}w{n}^{4}{g}^{2}{d}^{2}sArranget{e}^{3}\imath \).
\[-2hf{o}^{2}{l}^{2}w{n}^{4}{g}^{2}{d}^{2}sArranget{e}^{3}\imath -999,90-9,-99-09-99,100\]
Regroup terms.
\[-2Arranget{e}^{3}\imath hf{o}^{2}{l}^{2}w{n}^{4}{g}^{2}{d}^{2}s-999,90-9,-99-09-99,100\]
Regroup terms.
\[-999-2Arranget{e}^{3}\imath hf{o}^{2}{l}^{2}w{n}^{4}{g}^{2}{d}^{2}s,90-9,-99-09-99,100\]
Simplify  \(90-9\)  to  \(81\).
\[-999-2Arranget{e}^{3}\imath hf{o}^{2}{l}^{2}w{n}^{4}{g}^{2}{d}^{2}s,81,-99-09-99,100\]
Simplify  \(-99-09\)  to  \(-108\).
\[-999-2Arranget{e}^{3}\imath hf{o}^{2}{l}^{2}w{n}^{4}{g}^{2}{d}^{2}s,81,-108-99,100\]
Simplify  \(-108-99\)  to  \(-207\).
\[-999-2Arranget{e}^{3}\imath hf{o}^{2}{l}^{2}w{n}^{4}{g}^{2}{d}^{2}s,81,-207,100\]