$$\left. \begin{array} { l } { \quad ( \frac { 7 } { 5 } ) ^ { 2 x } = ( \frac { 45 } { 25 } ) ^ { 3 } } \end{array} \right.$$
$x = \frac{3 \log_{\frac{7}{5}} {(\frac{9}{5})}}{2} \approx 2.620364777$
$$\left(\frac{7}{5}\right)^{2x}=\frac{729}{125}$$
$$\log(\left(\frac{7}{5}\right)^{2x})=\log(\frac{729}{125})$$
$$2x\log(\frac{7}{5})=\log(\frac{729}{125})$$
$$2x=\frac{\log(\frac{729}{125})}{\log(\frac{7}{5})}$$
$$2x=\log_{\frac{7}{5}}\left(\frac{729}{125}\right)$$
$$x=\frac{\ln(\frac{729}{125})}{2\ln(\frac{7}{5})}$$
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