$$\left. \begin{array} { l } { x - \frac { 1 } { 4 } ( x - \frac { 2 - x } { 6 } ) = \frac { 2 x + 8 } { 3 } - 3 } \end{array} \right.$$
$x=-10$
$$12x-3\left(x-\frac{2-x}{6}\right)=4\left(2x+8\right)-36$$
$$12x-3\left(x-\frac{2-x}{6}\right)=8x+32-36$$
$$12x-3\left(x-\frac{2-x}{6}\right)=8x-4$$
$$12x-3\left(x-\left(\frac{1}{3}-\frac{1}{6}x\right)\right)=8x-4$$
$$12x-3\left(x-\frac{1}{3}-\left(-\frac{1}{6}x\right)\right)=8x-4$$
$$12x-3\left(x-\frac{1}{3}+\frac{1}{6}x\right)=8x-4$$
$$12x-3\left(\frac{7}{6}x-\frac{1}{3}\right)=8x-4$$
$$12x-3\times \frac{7}{6}x-3\left(-\frac{1}{3}\right)=8x-4$$
$$12x+\frac{-3\times 7}{6}x-3\left(-\frac{1}{3}\right)=8x-4$$
$$12x+\frac{-21}{6}x-3\left(-\frac{1}{3}\right)=8x-4$$
$$12x-\frac{7}{2}x-3\left(-\frac{1}{3}\right)=8x-4$$
$$12x-\frac{7}{2}x+1=8x-4$$
$$\frac{17}{2}x+1=8x-4$$
$$\frac{17}{2}x+1-8x=-4$$
$$\frac{1}{2}x+1=-4$$
$$\frac{1}{2}x=-4-1$$
$$\frac{1}{2}x=-5$$
$$x=-5\times 2$$
$$x=-10$$
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