$$\left. \begin{array} { l } { x + y ^ { 2 } + 4 z ^ { 2 } = 0 } \end{array} \right.$$
$x=-\left(y^{2}+4z^{2}\right)$
$$x+4z^{2}=-y^{2}$$
$$x=-y^{2}-4z^{2}$$
Show Solution
Hide Solution
