Solve Solve the given qu QUESTION 1 x ^ 2 = 4 ( a ) | Equatix - Math Solver

Fractions & Decimals

Ratios & Proportions

Basic Number Theory

Integers & Absolute Values

Factors & Multiples

Prime Factorization

Basic Equations & Inequalities

Coordinate Plane & Graphing

Linear Equations & Inequalities

Quadratic Equations

Polynomials & Factoring

Functions & Graphs

Systems of Equations

Trigonometric Functions

Trigonometric Identities & Equations

Right Triangle Trigonometry

Graphing Trigonometric Functions

Limits & Continuity

Derivatives & Applications

Integrals & Applications

Series & Sequences

Multivariable Calculus

Functions & Graphs

Polynomial & Rational Functions

Exponential & Logarithmic Functions

Sequences & Series

Descriptive Statistics

Normal Distribution

Hypothesis Testing

Regression Analysis

Linear Programming

Sets & Counting

Eigenvalues & Eigenvectors

Linear Transformations

Atomic Structure

Thermochemistry

Example

3(r+2s)=2t-4

a⋅(b-2)=3b

3(r+2s)=2t-4

a⋅(b-2)=3b

Question

$$\left. \begin{array} { l } { x ^ { 2 } = 4 } \end{array} \right.$$

Solve for x

$x=2$
$x=-2$

Steps Using Difference of Squares

Steps by Finding Square Root

Steps Using the Quadratic Formula

Steps Using Difference of Squares

Subtract $4$ from both sides.

$$x^{2}-4=0$$

Consider $x^{2}-4$. Rewrite $x^{2}-4$ as $x^{2}-2^{2}$. The difference of squares can be factored using the rule: $a^{2}-b^{2}=\left(a-b\right)\left(a+b\right)$.

$$\left(x-2\right)\left(x+2\right)=0$$

To find equation solutions, solve $x-2=0$ and $x+2=0$.

$$x=2$$ $$x=-2$$

Steps by Finding Square Root

Take the square root of both sides of the equation.

$$x=2$$ $$x=-2$$

Steps Using the Quadratic Formula

Subtract $4$ from both sides.

$$x^{2}-4=0$$

This equation is in standard form: $ax^{2}+bx+c=0$. Substitute $1$ for $a$, $0$ for $b$, and $-4$ for $c$ in the quadratic formula, $\frac{-b±\sqrt{b^{2}-4ac}}{2a}$.

$$x=\frac{0±\sqrt{0^{2}-4\left(-4\right)}}{2}$$

Square $0$.

$$x=\frac{0±\sqrt{-4\left(-4\right)}}{2}$$

Multiply $-4$ times $-4$.

$$x=\frac{0±\sqrt{16}}{2}$$

Take the square root of $16$.

$$x=\frac{0±4}{2}$$

Now solve the equation $x=\frac{0±4}{2}$ when $±$ is plus. Divide $4$ by $2$.

$$x=2$$

Now solve the equation $x=\frac{0±4}{2}$ when $±$ is minus. Divide $-4$ by $2$.

$$x=-2$$

The equation is now solved.

$$x=2$$ $$x=-2$$