Question

$$\left. \begin{array} { l } { x ^ { 2 } + 2 x ^ { 2 } y + 3 x ^ { 2 } y + \frac { 1 } { y } } \\ { 4 x ^ { 3 } + 3 x ^ { 2 } y + 6 x y ^ { 2 } + 4 y ^ { 3 } } \\ { 001 : } \end{array} \right.$$

Answer

$$128*In*X*x^3+3*x^2*y+6*x*y^2+4*y^3$$

Solution


Simplify  \(In\times 32X\times 4{x}^{3}\)  to  \(128X{x}^{3}In\).
\[128X{x}^{3}In+3{x}^{2}y+6x{y}^{2}+4{y}^{3}\]
Regroup terms.
\[128InX{x}^{3}+3{x}^{2}y+6x{y}^{2}+4{y}^{3}\]