Solve augmented matrix methods. 56. x_{1} + 3x_{2} = 1; 3x_{1} - 2x_{2} = 14 | Equatix - Math Solver

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Example

3(r+2s)=2t-4

a⋅(b-2)=3b

3(r+2s)=2t-4

a⋅(b-2)=3b

Question

$$\left. \begin{array} { l } { x _ { 1 } + 3 x _ { 2 } = 1 } \\ { - 2 x _ { 2 } = 14 } \end{array} \right.$$

Solve for x_1, x_2

$x_{1}=22$
$x_{2}=-7$

Solution Steps

Consider the second equation. Divide both sides by $-2$.

$$x_{2}=\frac{14}{-2}$$

Divide $14$ by $-2$ to get $-7$.

$$x_{2}=-7$$

Consider the first equation. Insert the known values of variables into the equation.

$$x_{1}+3\left(-7\right)=1$$

Multiply $3$ and $-7$ to get $-21$.

$$x_{1}-21=1$$

Add $21$ to both sides.

$$x_{1}=1+21$$

Add $1$ and $21$ to get $22$.

$$x_{1}=22$$

The system is now solved.

$$x_{1}=22$$ $$x_{2}=-7$$