Solve for \(y\) in \(\frac{y}{\frac{31}{5}}=\frac{\frac{41}{2}}{\frac{21}{4}}\).
Solve for \(y\).
\[\frac{y}{\frac{31}{5}}=\frac{\frac{41}{2}}{\frac{21}{4}}\]
Invert and multiply.
\[y\times \frac{5}{31}=\frac{\frac{41}{2}}{\frac{21}{4}}\]
Simplify \(y\times \frac{5}{31}\) to \(\frac{y\times 5}{31}\).
\[\frac{y\times 5}{31}=\frac{\frac{41}{2}}{\frac{21}{4}}\]
Regroup terms.
\[\frac{5y}{31}=\frac{\frac{41}{2}}{\frac{21}{4}}\]
Invert and multiply.
\[\frac{5y}{31}=\frac{41}{2}\times \frac{4}{21}\]
Use this rule: \(\frac{a}{b} \times \frac{c}{d}=\frac{ac}{bd}\).
\[\frac{5y}{31}=\frac{41\times 4}{2\times 21}\]
Simplify \(41\times 4\) to \(164\).
\[\frac{5y}{31}=\frac{164}{2\times 21}\]
Simplify \(2\times 21\) to \(42\).
\[\frac{5y}{31}=\frac{164}{42}\]
Simplify \(\frac{164}{42}\) to \(\frac{82}{21}\).
\[\frac{5y}{31}=\frac{82}{21}\]
Multiply both sides by \(31\).
\[5y=\frac{82}{21}\times 31\]
Use this rule: \(\frac{a}{b} \times c=\frac{ac}{b}\).
\[5y=\frac{82\times 31}{21}\]
Simplify \(82\times 31\) to \(2542\).
\[5y=\frac{2542}{21}\]
Divide both sides by \(5\).
\[y=\frac{\frac{2542}{21}}{5}\]
Simplify \(\frac{\frac{2542}{21}}{5}\) to \(\frac{2542}{21\times 5}\).
\[y=\frac{2542}{21\times 5}\]
Simplify \(21\times 5\) to \(105\).
\[y=\frac{2542}{105}\]
\[y=\frac{2542}{105}\]
Substitute \(y=\frac{2542}{105}\) into \(\frac{IIy}{51},6=\frac{IIy}{51},6,11,\frac{2}{34},4\).
Start with the original equation.
\[\frac{IIy}{51},6=\frac{IIy}{51},6,11,\frac{2}{34},4\]
Let \(y=\frac{2542}{105}\).
\[\frac{IIy}{51},6=\frac{IIy}{51},6,11,\frac{2}{34},4\]
Simplify.
\[\frac{IIy}{51},6=\frac{IIy}{51},6,11,\frac{1}{17},4\]
\[\frac{IIy}{51},6=\frac{IIy}{51},6,11,\frac{1}{17},4\]
Since \(\frac{IIy}{51},6=\frac{IIy}{51},6,11,\frac{1}{17},4\) is not true, this is an inconsistent system.
