Question

$$\left. \begin{array} { l } { 1 ? } \\ { 12 , 13 ( 2 ) 12 , 14 , 15 , 15 \right.$$

Answer

$$12*Th*eHCFofwhichofth*efollowingpairsofnumbersisnot,312,588,1200,29*IM*p*l*a^2*n^2*t*o$$

Solution


Simplify  \(TheHCFofwhichofthefollowingpairsofnumbersisnot\times 1\times 1\times 12\)  to  \(12TheHCFofwhichofthefollowingpairsofnumbersisnot\).
\[12TheHCFofwhichofthefollowingpairsofnumbersisnot,13\times 2\times 12,14\times 3\times 14,15\times 4\times 20,29planat\imath on\]
Simplify  \(13\times 2\)  to  \(26\).
\[12TheHCFofwhichofthefollowingpairsofnumbersisnot,26\times 12,14\times 3\times 14,15\times 4\times 20,29planat\imath on\]
Simplify  \(26\times 12\)  to  \(312\).
\[12TheHCFofwhichofthefollowingpairsofnumbersisnot,312,14\times 3\times 14,15\times 4\times 20,29planat\imath on\]
Simplify  \(14\times 3\)  to  \(42\).
\[12TheHCFofwhichofthefollowingpairsofnumbersisnot,312,42\times 14,15\times 4\times 20,29planat\imath on\]
Simplify  \(42\times 14\)  to  \(588\).
\[12TheHCFofwhichofthefollowingpairsofnumbersisnot,312,588,15\times 4\times 20,29planat\imath on\]
Simplify  \(15\times 4\)  to  \(60\).
\[12TheHCFofwhichofthefollowingpairsofnumbersisnot,312,588,60\times 20,29planat\imath on\]
Simplify  \(60\times 20\)  to  \(1200\).
\[12TheHCFofwhichofthefollowingpairsofnumbersisnot,312,588,1200,29planat\imath on\]
Use Product Rule: \({x}^{a}{x}^{b}={x}^{a+b}\).
\[12TheHCFofwhichofthefollowingpairsofnumbersisnot,312,588,1200,29pl{a}^{2}{n}^{2}t\imath o\]
Regroup terms.
\[12TheHCFofwhichofthefollowingpairsofnumbersisnot,312,588,1200,29\imath pl{a}^{2}{n}^{2}to\]