How to solve Page No : Date

1. Factor the equation (x + 2)(x + 3) = 0. 2. Set each factor equal to zero: x + 2 = 0 and x + 3 = 0. 3. Solve for x: x = -2 and x = -3.

Solve Page No : Date | Equatix

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$$\left. \begin{array} { l } { 1 } \\ { 6 / 424 } \end{array} \right.$$

$\frac{3}{212},1$

Reduce the fraction $\frac{6}{424}$ to lowest terms by extracting and canceling out $2$.

$$sort(1,\frac{3}{212})$$

Convert decimal numbers in the list $1,\frac{3}{212}$ to fractions.

$$1,\frac{3}{212}$$

To sort the list, start from a single element $1$.

$$1$$

Insert $\frac{3}{212}$ to the appropriate location in the new list.

$$\frac{3}{212},1$$

$1,\ \frac{3}{212}$