$$\left. \begin{array} { l } { 10. } \\ { 21 b - 32 + 7 b - 20 b } \end{array} \right.$$
$40\left(b-4\right)$
$$10=2\times 5$$ $$-32+8b=8\left(b-4\right)$$
$$40\left(b-4\right)$$
$$40b-160$$
Show Solution
Hide Solution
$10,\ 8\left(b-4\right)$