Question

$$\left. \begin{array} { l } { 10 ( m + 1 ) = 4 \quad a b , c } \\ { 1 \cdot 5 x ^ { 2 } - 2 x + 3 = 0 } \end{array} \right.$$

Answer

$$n=(2*x-3)/(5*Id*e*IM*t*f*y*a*b*c*x^2)$$

Solution


Regroup terms.
\[5Ide\imath ntfyabc{x}^{2}-2x+3=0\]
Add \(2x\) to both sides.
\[5Ide\imath ntfyabc{x}^{2}+3=2x\]
Regroup terms.
\[3+5Ide\imath ntfyabc{x}^{2}=2x\]
Subtract \(3\) from both sides.
\[5Ide\imath ntfyabc{x}^{2}=2x-3\]
Divide both sides by \(5\).
\[Ide\imath ntfyabc{x}^{2}=\frac{2x-3}{5}\]
Divide both sides by \(Id\).
\[e\imath ntfyabc{x}^{2}=\frac{\frac{2x-3}{5}}{Id}\]
Simplify  \(\frac{\frac{2x-3}{5}}{Id}\)  to  \(\frac{2x-3}{5Id}\).
\[e\imath ntfyabc{x}^{2}=\frac{2x-3}{5Id}\]
Divide both sides by \(e\).
\[\imath ntfyabc{x}^{2}=\frac{\frac{2x-3}{5Id}}{e}\]
Simplify  \(\frac{\frac{2x-3}{5Id}}{e}\)  to  \(\frac{2x-3}{5Ide}\).
\[\imath ntfyabc{x}^{2}=\frac{2x-3}{5Ide}\]
Divide both sides by \(\imath \).
\[ntfyabc{x}^{2}=\frac{\frac{2x-3}{5Ide}}{\imath }\]
Simplify  \(\frac{\frac{2x-3}{5Ide}}{\imath }\)  to  \(\frac{2x-3}{5Ide\imath }\).
\[ntfyabc{x}^{2}=\frac{2x-3}{5Ide\imath }\]
Divide both sides by \(t\).
\[nfyabc{x}^{2}=\frac{\frac{2x-3}{5Ide\imath }}{t}\]
Simplify  \(\frac{\frac{2x-3}{5Ide\imath }}{t}\)  to  \(\frac{2x-3}{5Ide\imath t}\).
\[nfyabc{x}^{2}=\frac{2x-3}{5Ide\imath t}\]
Divide both sides by \(f\).
\[nyabc{x}^{2}=\frac{\frac{2x-3}{5Ide\imath t}}{f}\]
Simplify  \(\frac{\frac{2x-3}{5Ide\imath t}}{f}\)  to  \(\frac{2x-3}{5Ide\imath tf}\).
\[nyabc{x}^{2}=\frac{2x-3}{5Ide\imath tf}\]
Divide both sides by \(y\).
\[nabc{x}^{2}=\frac{\frac{2x-3}{5Ide\imath tf}}{y}\]
Simplify  \(\frac{\frac{2x-3}{5Ide\imath tf}}{y}\)  to  \(\frac{2x-3}{5Ide\imath tfy}\).
\[nabc{x}^{2}=\frac{2x-3}{5Ide\imath tfy}\]
Divide both sides by \(a\).
\[nbc{x}^{2}=\frac{\frac{2x-3}{5Ide\imath tfy}}{a}\]
Simplify  \(\frac{\frac{2x-3}{5Ide\imath tfy}}{a}\)  to  \(\frac{2x-3}{5Ide\imath tfya}\).
\[nbc{x}^{2}=\frac{2x-3}{5Ide\imath tfya}\]
Divide both sides by \(b\).
\[nc{x}^{2}=\frac{\frac{2x-3}{5Ide\imath tfya}}{b}\]
Simplify  \(\frac{\frac{2x-3}{5Ide\imath tfya}}{b}\)  to  \(\frac{2x-3}{5Ide\imath tfyab}\).
\[nc{x}^{2}=\frac{2x-3}{5Ide\imath tfyab}\]
Divide both sides by \(c\).
\[n{x}^{2}=\frac{\frac{2x-3}{5Ide\imath tfyab}}{c}\]
Simplify  \(\frac{\frac{2x-3}{5Ide\imath tfyab}}{c}\)  to  \(\frac{2x-3}{5Ide\imath tfyabc}\).
\[n{x}^{2}=\frac{2x-3}{5Ide\imath tfyabc}\]
Divide both sides by \({x}^{2}\).
\[n=\frac{\frac{2x-3}{5Ide\imath tfyabc}}{{x}^{2}}\]
Simplify  \(\frac{\frac{2x-3}{5Ide\imath tfyabc}}{{x}^{2}}\)  to  \(\frac{2x-3}{5Ide\imath tfyabc{x}^{2}}\).
\[n=\frac{2x-3}{5Ide\imath tfyabc{x}^{2}}\]