Question

$$\left. \begin{array} { l } { 10.4 } \\ { \frac { - 2 } { 8 } , \frac { - 1 } { - 325 } , \frac { - \frac { 5 } { 7 } } { 7 } , \right.$$

Answer

$$-1/4+e^3*IM*w*a*r^3*k*s*h*t*n*o*d,1/(225/14-)$$

Solution


Move the negative sign to the left.
\[warksheet\imath norder-\frac{2}{8},\frac{-\frac{1}{35\times \frac{5}{7}}}{-\frac{9}{14}-}\]
Use this rule: \(a \times \frac{b}{c}=\frac{ab}{c}\).
\[warksheet\imath norder-\frac{2}{8},\frac{-\frac{1}{\frac{35\times 5}{7}}}{-\frac{9}{14}-}\]
Simplify  \(35\times 5\)  to  \(175\).
\[warksheet\imath norder-\frac{2}{8},\frac{-\frac{1}{\frac{175}{7}}}{-\frac{9}{14}-}\]
Simplify  \(\frac{175}{7}\)  to  \(25\).
\[warksheet\imath norder-\frac{2}{8},\frac{-\frac{1}{25}}{-\frac{9}{14}-}\]
Regroup terms.
\[warrrkshtnodee\imath e-\frac{2}{8},\frac{-\frac{1}{25}}{-\frac{9}{14}-}\]
Simplify  \(warrrkshtnodee\imath e\)  to  \(wa{r}^{3}kshtnodee\imath e\).
\[wa{r}^{3}kshtnodee\imath e-\frac{2}{8},\frac{-\frac{1}{25}}{-\frac{9}{14}-}\]
Use Product Rule: \({x}^{a}{x}^{b}={x}^{a+b}\).
\[wa{r}^{3}kshtnod{e}^{3}\imath -\frac{2}{8},\frac{-\frac{1}{25}}{-\frac{9}{14}-}\]
Regroup terms.
\[{e}^{3}\imath wa{r}^{3}kshtnod-\frac{2}{8},\frac{-\frac{1}{25}}{-\frac{9}{14}-}\]
Simplify  \(\frac{2}{8}\)  to  \(\frac{1}{4}\).
\[{e}^{3}\imath wa{r}^{3}kshtnod-\frac{1}{4},\frac{-\frac{1}{25}}{-\frac{9}{14}-}\]
Two negatives make a positive.
\[{e}^{3}\imath wa{r}^{3}kshtnod-\frac{1}{4},\frac{\frac{1}{25}}{\frac{9}{14}-}\]
Simplify  \(\frac{\frac{1}{25}}{\frac{9}{14}-}\)  to  \(\frac{1}{25\times \frac{9}{14}-}\).
\[{e}^{3}\imath wa{r}^{3}kshtnod-\frac{1}{4},\frac{1}{25\times \frac{9}{14}-}\]
Use this rule: \(a \times \frac{b}{c}=\frac{ab}{c}\).
\[{e}^{3}\imath wa{r}^{3}kshtnod-\frac{1}{4},\frac{1}{\frac{25\times 9}{14}-}\]
Simplify  \(25\times 9\)  to  \(225\).
\[{e}^{3}\imath wa{r}^{3}kshtnod-\frac{1}{4},\frac{1}{\frac{225}{14}-}\]
Regroup terms.
\[-\frac{1}{4}+{e}^{3}\imath wa{r}^{3}kshtnod,\frac{1}{\frac{225}{14}-}\]