Question

$$\left. \begin{array} { l } { 123 + 879 - 545 + 423 - 639 = ? } \\ { 351 } \\ { 281 } \end{array} \right.$$

Answer

[No Solution]

Solution


Simplify  \(1\times 351\)  to  \(351\).
\[123+879-545+423-639=351\times 2\times 421241\times 4\times 281\times 5\times 21.1\]
Simplify  \(351\times 2\)  to  \(702\).
\[123+879-545+423-639=702\times 421241\times 4\times 281\times 5\times 21.1\]
Simplify  \(702\times 421241\)  to  \(295711182\).
\[123+879-545+423-639=295711182\times 4\times 281\times 5\times 21.1\]
Simplify  \(295711182\times 4\)  to  \(1182844728\).
\[123+879-545+423-639=1182844728\times 281\times 5\times 21.1\]
Simplify  \(1182844728\times 281\)  to  \(332379368568\).
\[123+879-545+423-639=332379368568\times 5\times 21.1\]
Simplify  \(332379368568\times 5\)  to  \(1.661897\times {10}^{12}\).
\[123+879-545+423-639=1.661897\times {10}^{12}\times 21.1\]
Simplify  \(1.661897\times {10}^{12}\times 21.1\)  to  \((35.066023)\times {10}^{12}\).
\[123+879-545+423-639=35.066023\times {10}^{12}\]
Simplify  \(123+879\)  to  \(1002\).
\[1002-545+423-639=35.066023\times {10}^{12}\]
Simplify  \(1002-545\)  to  \(457\).
\[457+423-639=35.066023\times {10}^{12}\]
Simplify  \(457+423\)  to  \(880\).
\[880-639=35.066023\times {10}^{12}\]
Simplify  \(880-639\)  to  \(241\).
\[241=35.066023\times {10}^{12}\]
Since \(241=35.066023\times {10}^{12}\) is false, there is no solution.
No Solution