Question

$$\left. \begin{array} { l } { 150 d x = 150 = 10000 x = } \\ { 25 e + 00 a n d } \end{array} \right.$$

Answer

$$v=1/(25*Co*e*n^2*r*t^2*o*a*d)$$

Solution


Divide both sides by \(Co\).
\[\frac{1}{Co}=nvert\times 25toand\]
Use Product Rule: \({x}^{a}{x}^{b}={x}^{a+b}\).
\[\frac{1}{Co}={n}^{2}ver{t}^{2}\times 25oad\]
Regroup terms.
\[\frac{1}{Co}=25e{n}^{2}vr{t}^{2}oad\]
Divide both sides by \(25\).
\[\frac{\frac{1}{Co}}{25}=e{n}^{2}vr{t}^{2}oad\]
Simplify  \(\frac{\frac{1}{Co}}{25}\)  to  \(\frac{1}{25Co}\).
\[\frac{1}{25Co}=e{n}^{2}vr{t}^{2}oad\]
Divide both sides by \(e\).
\[\frac{\frac{1}{25Co}}{e}={n}^{2}vr{t}^{2}oad\]
Simplify  \(\frac{\frac{1}{25Co}}{e}\)  to  \(\frac{1}{25Coe}\).
\[\frac{1}{25Coe}={n}^{2}vr{t}^{2}oad\]
Divide both sides by \({n}^{2}\).
\[\frac{\frac{1}{25Coe}}{{n}^{2}}=vr{t}^{2}oad\]
Simplify  \(\frac{\frac{1}{25Coe}}{{n}^{2}}\)  to  \(\frac{1}{25Coe{n}^{2}}\).
\[\frac{1}{25Coe{n}^{2}}=vr{t}^{2}oad\]
Divide both sides by \(r\).
\[\frac{\frac{1}{25Coe{n}^{2}}}{r}=v{t}^{2}oad\]
Simplify  \(\frac{\frac{1}{25Coe{n}^{2}}}{r}\)  to  \(\frac{1}{25Coe{n}^{2}r}\).
\[\frac{1}{25Coe{n}^{2}r}=v{t}^{2}oad\]
Divide both sides by \({t}^{2}\).
\[\frac{\frac{1}{25Coe{n}^{2}r}}{{t}^{2}}=voad\]
Simplify  \(\frac{\frac{1}{25Coe{n}^{2}r}}{{t}^{2}}\)  to  \(\frac{1}{25Coe{n}^{2}r{t}^{2}}\).
\[\frac{1}{25Coe{n}^{2}r{t}^{2}}=voad\]
Divide both sides by \(o\).
\[\frac{\frac{1}{25Coe{n}^{2}r{t}^{2}}}{o}=vad\]
Simplify  \(\frac{\frac{1}{25Coe{n}^{2}r{t}^{2}}}{o}\)  to  \(\frac{1}{25Coe{n}^{2}r{t}^{2}o}\).
\[\frac{1}{25Coe{n}^{2}r{t}^{2}o}=vad\]
Divide both sides by \(a\).
\[\frac{\frac{1}{25Coe{n}^{2}r{t}^{2}o}}{a}=vd\]
Simplify  \(\frac{\frac{1}{25Coe{n}^{2}r{t}^{2}o}}{a}\)  to  \(\frac{1}{25Coe{n}^{2}r{t}^{2}oa}\).
\[\frac{1}{25Coe{n}^{2}r{t}^{2}oa}=vd\]
Divide both sides by \(d\).
\[\frac{\frac{1}{25Coe{n}^{2}r{t}^{2}oa}}{d}=v\]
Simplify  \(\frac{\frac{1}{25Coe{n}^{2}r{t}^{2}oa}}{d}\)  to  \(\frac{1}{25Coe{n}^{2}r{t}^{2}oad}\).
\[\frac{1}{25Coe{n}^{2}r{t}^{2}oad}=v\]
Switch sides.
\[v=\frac{1}{25Coe{n}^{2}r{t}^{2}oad}\]