1. Factor the equation (x + 2)(x + 3) = 0. 2. Set each factor equal to zero: x + 2 = 0 and x + 3 = 0. 3. Solve for x: x = -2 and x = -3.

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Question

$$\left. \begin{array} { l } { 2 x - 1 = 14 } \\ { x } \end{array} \right.$$

$y = \frac{15}{2} = 7\frac{1}{2} = 7.5$

Consider the first equation. Add $1$ to both sides.

$$2x=14+1$$

Add $14$ and $1$ to get $15$.

$$2x=15$$

Divide both sides by $2$.

$$x=\frac{15}{2}$$

Consider the second equation. Insert the known values of variables into the equation.

$$y=\frac{15}{2}$$

The system is now solved.

$$x=\frac{15}{2}$$ $$y=\frac{15}{2}$$