$$\left. \begin{array} { l } { 20 } \\ { 3 ( x + 1 ) + x ^ { 2 } = x ^ { 2 } + 12 } \end{array} \right.$$
$y=20$
$$3x+3+x^{2}=x^{2}+12$$
$$3x+3+x^{2}-x^{2}=12$$
$$3x+3=12$$
$$3x=12-3$$
$$3x=9$$
$$x=\frac{9}{3}$$
$$x=3$$
$$x=3$$ $$y=20$$
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