Question

$$\left. \begin{array} { l } { 3 a ^ { 2 } - 2 a + 5 a = } \\ { 2 , \quad 0 , \quad c - 2 , d - 4 } \end{array} \right.$$

Answer

$$l=(2*(a,0,2,d-2+a)-5*IM*f*a)/(3*Ev*e*a^4*u*t)$$

Solution


Regroup terms.
\[3aa{a}^{2}lutEve-2a+5\imath fa=a\times 2,b\times 0,2,d-4\]
Use Product Rule: \({x}^{a}{x}^{b}={x}^{a+b}\).
\[3{a}^{1+1+2}lutEve-2a+5\imath fa=a\times 2,b\times 0,2,d-4\]
Simplify  \(1+1\)  to  \(2\).
\[3{a}^{2+2}lutEve-2a+5\imath fa=a\times 2,b\times 0,2,d-4\]
Simplify  \(2+2\)  to  \(4\).
\[3{a}^{4}lutEve-2a+5\imath fa=a\times 2,b\times 0,2,d-4\]
Regroup terms.
\[3Eve{a}^{4}lut-2a+5\imath fa=a\times 2,b\times 0,2,d-4\]
Regroup terms.
\[3Eve{a}^{4}lut-2a+5\imath fa=2a,b\times 0,2,d-4\]
Simplify  \(b\times 0\)  to  \(0\).
\[3Eve{a}^{4}lut-2a+5\imath fa=2a,0,2,d-4\]
Factor out the common term \(2\).
\[3Eve{a}^{4}lut-2a+5\imath fa=2((a,0,2,d)-2)\]
Add \(2a\) to both sides.
\[3Eve{a}^{4}lut+5\imath fa=2((a,0,2,d)-2)+2a\]
Factor out the common term \(2\).
\[3Eve{a}^{4}lut+5\imath fa=2((a,0,2,d)-2+(a))\]
Subtract \(5\imath fa\) from both sides.
\[3Eve{a}^{4}lut=2((a,0,2,d)-2+a)-5\imath fa\]
Simplify  \((a,0,2,d)-2+a\)  to  \(a,0,2,d-2+a\).
\[3Eve{a}^{4}lut=2(a,0,2,d-2+a)-5\imath fa\]
Divide both sides by \(3\).
\[Eve{a}^{4}lut=\frac{2(a,0,2,d-2+a)-5\imath fa}{3}\]
Divide both sides by \(Ev\).
\[e{a}^{4}lut=\frac{\frac{2(a,0,2,d-2+a)-5\imath fa}{3}}{Ev}\]
Simplify  \(\frac{\frac{2(a,0,2,d-2+a)-5\imath fa}{3}}{Ev}\)  to  \(\frac{2(a,0,2,d-2+a)-5\imath fa}{3Ev}\).
\[e{a}^{4}lut=\frac{2(a,0,2,d-2+a)-5\imath fa}{3Ev}\]
Divide both sides by \(e\).
\[{a}^{4}lut=\frac{\frac{2(a,0,2,d-2+a)-5\imath fa}{3Ev}}{e}\]
Simplify  \(\frac{\frac{2(a,0,2,d-2+a)-5\imath fa}{3Ev}}{e}\)  to  \(\frac{2(a,0,2,d-2+a)-5\imath fa}{3Eve}\).
\[{a}^{4}lut=\frac{2(a,0,2,d-2+a)-5\imath fa}{3Eve}\]
Divide both sides by \({a}^{4}\).
\[lut=\frac{\frac{2(a,0,2,d-2+a)-5\imath fa}{3Eve}}{{a}^{4}}\]
Simplify  \(\frac{\frac{2(a,0,2,d-2+a)-5\imath fa}{3Eve}}{{a}^{4}}\)  to  \(\frac{2(a,0,2,d-2+a)-5\imath fa}{3Eve{a}^{4}}\).
\[lut=\frac{2(a,0,2,d-2+a)-5\imath fa}{3Eve{a}^{4}}\]
Divide both sides by \(u\).
\[lt=\frac{\frac{2(a,0,2,d-2+a)-5\imath fa}{3Eve{a}^{4}}}{u}\]
Simplify  \(\frac{\frac{2(a,0,2,d-2+a)-5\imath fa}{3Eve{a}^{4}}}{u}\)  to  \(\frac{2(a,0,2,d-2+a)-5\imath fa}{3Eve{a}^{4}u}\).
\[lt=\frac{2(a,0,2,d-2+a)-5\imath fa}{3Eve{a}^{4}u}\]
Divide both sides by \(t\).
\[l=\frac{\frac{2(a,0,2,d-2+a)-5\imath fa}{3Eve{a}^{4}u}}{t}\]
Simplify  \(\frac{\frac{2(a,0,2,d-2+a)-5\imath fa}{3Eve{a}^{4}u}}{t}\)  to  \(\frac{2(a,0,2,d-2+a)-5\imath fa}{3Eve{a}^{4}ut}\).
\[l=\frac{2(a,0,2,d-2+a)-5\imath fa}{3Eve{a}^{4}ut}\]