Solve for \(x\) in \(63-5x+1=0CEN\).
Solve for \(x\).
\[63-5x+1=0CEN\]
Simplify \(0CEN\) to \(0\).
\[63-5x+1=0\]
Simplify \(63-5x+1\) to \(-5x+64\).
\[-5x+64=0\]
Subtract \(64\) from both sides.
\[-5x=-64\]
Divide both sides by \(-5\).
\[x=\frac{-64}{-5}\]
Two negatives make a positive.
\[x=\frac{64}{5}\]
\[x=\frac{64}{5}\]
Substitute \(x=\frac{64}{5}\) into \({x}^{2}\times 6x+q=0\).
Start with the original equation.
\[{x}^{2}\times 6x+q=0\]
Let \(x=\frac{64}{5}\).
\[{(\frac{64}{5})}^{2}\times 6\times \frac{64}{5}+q=0\]
Simplify.
\[\frac{1572864}{125}+q=0\]
\[\frac{1572864}{125}+q=0\]
Solve for \(q\) in \(\frac{1572864}{125}+q=0\).
Solve for \(q\).
\[\frac{1572864}{125}+q=0\]
Subtract \(\frac{1572864}{125}\) from both sides.
\[q=-\frac{1572864}{125}\]
\[q=-\frac{1572864}{125}\]
Therefore,
\[\begin{aligned}&q=-\frac{1572864}{125}\\&x=\frac{64}{5}\end{aligned}\]
q=-1572864/125;x=64/5
