Question

$$\left. \begin{array} { l } { 3.3 } \\ { ( 2 x - y , y - 3 x ) = ( 4.2 ) } \end{array} \right.$$

Answer

$$s=13.86/(Ex*e^2*IM*c^2*r*(-x-2*y))$$

Solution


Simplify  \(2x-y-y-3x\)  to  \(-x-2y\).
\[Excerc\imath se\div 3.3(-x-2y)=4.2\]
Use this rule: \(a\div \frac{b}{c}=a\times \frac{c}{b}\).
\[Excerc\imath se\times \frac{1}{3.3}(-x-2y)=4.2\]
Simplify  \(Excerc\imath se\times \frac{1}{3.3}(-x-2y)\)  to  \(\frac{Excerc\imath se(-x-2y)}{3.3}\).
\[\frac{Excerc\imath se(-x-2y)}{3.3}=4.2\]
Use Product Rule: \({x}^{a}{x}^{b}={x}^{a+b}\).
\[\frac{Ex{c}^{2}{e}^{2}r\imath s(-x-2y)}{3.3}=4.2\]
Regroup terms.
\[\frac{Ex{e}^{2}\imath {c}^{2}rs(-x-2y)}{3.3}=4.2\]
Multiply both sides by \(3.3\).
\[Ex{e}^{2}\imath {c}^{2}rs(-x-2y)=4.2\times 3.3\]
Simplify  \(4.2\times 3.3\)  to  \(13.86\).
\[Ex{e}^{2}\imath {c}^{2}rs(-x-2y)=13.86\]
Divide both sides by \(Ex\).
\[{e}^{2}\imath {c}^{2}rs(-x-2y)=\frac{13.86}{Ex}\]
Divide both sides by \({e}^{2}\).
\[\imath {c}^{2}rs(-x-2y)=\frac{\frac{13.86}{Ex}}{{e}^{2}}\]
Simplify  \(\frac{\frac{13.86}{Ex}}{{e}^{2}}\)  to  \(\frac{13.86}{Ex{e}^{2}}\).
\[\imath {c}^{2}rs(-x-2y)=\frac{13.86}{Ex{e}^{2}}\]
Divide both sides by \(\imath \).
\[{c}^{2}rs(-x-2y)=\frac{\frac{13.86}{Ex{e}^{2}}}{\imath }\]
Simplify  \(\frac{\frac{13.86}{Ex{e}^{2}}}{\imath }\)  to  \(\frac{13.86}{Ex{e}^{2}\imath }\).
\[{c}^{2}rs(-x-2y)=\frac{13.86}{Ex{e}^{2}\imath }\]
Divide both sides by \({c}^{2}\).
\[rs(-x-2y)=\frac{\frac{13.86}{Ex{e}^{2}\imath }}{{c}^{2}}\]
Simplify  \(\frac{\frac{13.86}{Ex{e}^{2}\imath }}{{c}^{2}}\)  to  \(\frac{13.86}{Ex{e}^{2}\imath {c}^{2}}\).
\[rs(-x-2y)=\frac{13.86}{Ex{e}^{2}\imath {c}^{2}}\]
Divide both sides by \(r\).
\[s(-x-2y)=\frac{\frac{13.86}{Ex{e}^{2}\imath {c}^{2}}}{r}\]
Simplify  \(\frac{\frac{13.86}{Ex{e}^{2}\imath {c}^{2}}}{r}\)  to  \(\frac{13.86}{Ex{e}^{2}\imath {c}^{2}r}\).
\[s(-x-2y)=\frac{13.86}{Ex{e}^{2}\imath {c}^{2}r}\]
Divide both sides by \(-x-2y\).
\[s=\frac{\frac{13.86}{Ex{e}^{2}\imath {c}^{2}r}}{-x-2y}\]
Simplify  \(\frac{\frac{13.86}{Ex{e}^{2}\imath {c}^{2}r}}{-x-2y}\)  to  \(\frac{13.86}{Ex{e}^{2}\imath {c}^{2}r(-x-2y)}\).
\[s=\frac{13.86}{Ex{e}^{2}\imath {c}^{2}r(-x-2y)}\]