Question

$$\left. \begin{array} { l } { 4 / 1 / 3 n - 2 } \\ { - 9 e ^ { 2 t } n - 1 n ^ { \right.$$

Answer

$$-(8*By*e^3*IM*w*h^2*c*n*u*m*b*r*d^3*v*t^2*o*g*A)/15$$

Solution


Simplify.
\[\frac{Bywh\imath chnumberd\imath v\imath dedtoget\times 8A}{15}\]
Regroup terms.
\[\frac{8whhcnumbrdddvttogABy\imath e\imath \imath ee}{15}\]
Simplify  \(8whhcnumbrdddvttogABy\imath e\imath \imath ee\)  to  \(8w{h}^{2}cnumbr{d}^{3}v{t}^{2}ogABy\imath e\imath \imath ee\).
\[\frac{8w{h}^{2}cnumbr{d}^{3}v{t}^{2}ogABy\imath e\imath \imath ee}{15}\]
Use Product Rule: \({x}^{a}{x}^{b}={x}^{a+b}\).
\[\frac{8w{h}^{2}cnumbr{d}^{3}v{t}^{2}ogABy{\imath }^{3}{e}^{3}}{15}\]
Isolate \({\imath }^{2}\).
\[\frac{8w{h}^{2}cnumbr{d}^{3}v{t}^{2}ogABy{\imath }^{2}\imath {e}^{3}}{15}\]
Use Square Rule: \({i}^{2}=-1\).
\[\frac{8w{h}^{2}cnumbr{d}^{3}v{t}^{2}ogABy\times -1\times \imath {e}^{3}}{15}\]
Simplify  \(8w{h}^{2}cnumbr{d}^{3}v{t}^{2}ogABy\times -1\times \imath {e}^{3}\)  to  \(-8w{h}^{2}cnumbr{d}^{3}v{t}^{2}ogABy\imath {e}^{3}\).
\[\frac{-8w{h}^{2}cnumbr{d}^{3}v{t}^{2}ogABy\imath {e}^{3}}{15}\]
Regroup terms.
\[\frac{-8By{e}^{3}\imath w{h}^{2}cnumbr{d}^{3}v{t}^{2}ogA}{15}\]
Move the negative sign to the left.
\[-\frac{8By{e}^{3}\imath w{h}^{2}cnumbr{d}^{3}v{t}^{2}ogA}{15}\]