Question

$$\left. \begin{array} { l } { 4 \cdot 5 \times \frac { 3 } { 5 } + 4 \cdot 5 \times \frac { 2 } { 5 } = ? } \\ { ( 1 ) 5 ( 2 ) 4 \quad ( 3 ) 2 \cdot 5 \quad ( 4 ) 4 \cdot 5 } \end{array} \right.$$

Answer

[No Solution]

Solution


Cancel \(5\).
\[4\times 3+4\times 5\times \frac{2}{5}=3\times 2-5\times 4\times 4-5\times 1\times 5\times 2\times 4\]
Simplify  \(4\times 3\)  to  \(12\).
\[12+4\times 5\times \frac{2}{5}=3\times 2-5\times 4\times 4-5\times 1\times 5\times 2\times 4\]
Cancel \(5\).
\[12+4\times 2=3\times 2-5\times 4\times 4-5\times 1\times 5\times 2\times 4\]
Simplify  \(4\times 2\)  to  \(8\).
\[12+8=3\times 2-5\times 4\times 4-5\times 1\times 5\times 2\times 4\]
Simplify  \(3\times 2\)  to  \(6\).
\[12+8=6-5\times 4\times 4-5\times 1\times 5\times 2\times 4\]
Simplify  \(5\times 4\)  to  \(20\).
\[12+8=6-20\times 4-5\times 1\times 5\times 2\times 4\]
Simplify  \(20\times 4\)  to  \(80\).
\[12+8=6-80-5\times 1\times 5\times 2\times 4\]
Simplify  \(5\times 1\)  to  \(5\).
\[12+8=6-80-5\times 5\times 2\times 4\]
Simplify  \(5\times 5\)  to  \(25\).
\[12+8=6-80-25\times 2\times 4\]
Simplify  \(25\times 2\)  to  \(50\).
\[12+8=6-80-50\times 4\]
Simplify  \(50\times 4\)  to  \(200\).
\[12+8=6-80-200\]
Simplify  \(12+8\)  to  \(20\).
\[20=6-80-200\]
Simplify  \(6-80\)  to  \(-74\).
\[20=-74-200\]
Simplify  \(-74-200\)  to  \(-274\).
\[20=-274\]
Since \(20=-274\) is false, there is no solution.
No Solution