$$\left. \begin{array} { l } { 4 x + 5 } \\ { x - 1 } \end{array} \right.$$
$\left(x-1\right)\left(4x+5\right)$
$$\left(x-1\right)\left(4x+5\right)$$
$$4x^{2}+x-5$$
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$4x+5,\ x-1$
