Regroup terms.
\[4321\imath y={1}^{x}\]
Use Definition of Common Logarithm: \({b}^{a}=x\) if and only if \(log_b(x)=a\).
\[\log_{1}{(4321\imath y)}=x\]
Since \(\log{1}=0\), then \(\log_{1}{(4321\imath y)}=\frac{\log{(4321\imath y)}}{\log{1}}=\frac{\log{(4321\imath y)}}{0}=\infty \).
\[\infty =x\]
Switch sides.
\[x=\infty \]
x=INF
