Solve 49 + 9 76-23 20 3 81/9\ Place value of 9 in 49 274 argest numeral from 5

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Question

$$\left. \begin{array} { l } { 49 + 9 } \\ { 76 - 23 } \\ { 20 \times 3 } \\ { 81 \div 9 } \\ { 9 49274 } \\ { 5 , 1 } \end{array} \right.$$

Sort

$1,5,9,53,58,60,949274$

Solution Steps

Add $49$ and $9$ to get $58$.

$$sort(58,76-23,20\times 3,\frac{81}{9},949274,5,1)$$

Subtract $23$ from $76$ to get $53$.

$$sort(58,53,20\times 3,\frac{81}{9},949274,5,1)$$

Multiply $20$ and $3$ to get $60$.

$$sort(58,53,60,\frac{81}{9},949274,5,1)$$

Divide $81$ by $9$ to get $9$.

$$sort(58,53,60,9,949274,5,1)$$

To sort the list, start from a single element $58$.

$$58$$

Insert $53$ to the appropriate location in the new list.

$$53,58$$

Insert $60$ to the appropriate location in the new list.

$$53,58,60$$

Insert $9$ to the appropriate location in the new list.

$$9,53,58,60$$

Insert $949274$ to the appropriate location in the new list.

$$9,53,58,60,949274$$

Insert $5$ to the appropriate location in the new list.

$$5,9,53,58,60,949274$$

Insert $1$ to the appropriate location in the new list.

$$1,5,9,53,58,60,949274$$

Show Solution

Evaluate

$58,\ 53,\ 60,\ 9,\ 949274,\ 5,\ 1$