Solve for \(b\) in \(5b+b=3b+14\).
Solve for \(b\).
\[5b+b=3b+14\]
Simplify \(5b+b\) to \(6b\).
\[6b=3b+14\]
Subtract \(3b\) from both sides.
\[6b-3b=14\]
Simplify \(6b-3b\) to \(3b\).
\[3b=14\]
Divide both sides by \(3\).
\[b=\frac{14}{3}\]
\[b=\frac{14}{3}\]
Substitute \(b=\frac{14}{3}\) into \(5b+1-3b=14b\).
Start with the original equation.
\[5b+1-3b=14b\]
Let \(b=\frac{14}{3}\).
\[5\times \frac{14}{3}+1-3\times \frac{14}{3}=14\times \frac{14}{3}\]
Simplify.
\[\frac{31}{3}=\frac{196}{3}\]
\[\frac{31}{3}=\frac{196}{3}\]
Since \(\frac{31}{3}=\frac{196}{3}\) is not true, this is an inconsistent system.
