Solve 5 + 2 * 3 / (3 * 2) * 3 ( a) 8 ( b) 7/6 ( c) 16/3 ( d ) 17 | Equatix - Math Solver

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Example

3(r+2s)=2t-4

a⋅(b-2)=3b

3(r+2s)=2t-4

a⋅(b-2)=3b

Question

$$\left. \begin{array} { l } { 5 + 2 \times 3 \div ( 3 \times 2 ) \times 3 } \\ { 8 } \\ { 7 / 6 } \\ { 16 / 3 } \\ { 17 } \end{array} \right.$$

Sort

$\frac{7}{6},\frac{16}{3},8,8,17$

Solution Steps

Divide $2\times 3$ by $3\times 2$ to get $1$.

$$sort(5+1\times 3,8,\frac{7}{6},\frac{16}{3},17)$$

Multiply $1$ and $3$ to get $3$.

$$sort(5+3,8,\frac{7}{6},\frac{16}{3},17)$$

Add $5$ and $3$ to get $8$.

$$sort(8,8,\frac{7}{6},\frac{16}{3},17)$$

Convert decimal numbers in the list $8,8,\frac{7}{6},\frac{16}{3},17$ to fractions.

$$8,8,\frac{7}{6},\frac{16}{3},17$$

Least common denominator of the numbers in the list $8,8,\frac{7}{6},\frac{16}{3},17$ is $6$. Convert numbers in the list to fractions with denominator $6$.

$$\frac{48}{6},\frac{48}{6},\frac{7}{6},\frac{32}{6},\frac{102}{6}$$

To sort the list, start from a single element $\frac{48}{6}$.

$$\frac{48}{6}$$

Insert $\frac{48}{6}$ to the appropriate location in the new list.

$$\frac{48}{6},\frac{48}{6}$$

Insert $\frac{7}{6}$ to the appropriate location in the new list.

$$\frac{7}{6},\frac{48}{6},\frac{48}{6}$$

Insert $\frac{32}{6}$ to the appropriate location in the new list.

$$\frac{7}{6},\frac{32}{6},\frac{48}{6},\frac{48}{6}$$

Insert $\frac{102}{6}$ to the appropriate location in the new list.

$$\frac{7}{6},\frac{32}{6},\frac{48}{6},\frac{48}{6},\frac{102}{6}$$

Replace the obtained fractions with the initial values.

$$\frac{7}{6},\frac{16}{3},8,8,17$$

Evaluate

$8,\ 8,\ \frac{7}{6},\ \frac{16}{3},\ 17$