Question

$$\left. \begin{array} { l } { 6128 + 582 = } \\ { 85 + ( - 96 ) = } \end{array} \right.$$

Answer

$$v=(-678+85*Ad*e**IM*d*t*h*f*o^2*l^2*w*n*g)/(6128*IM)$$

Solution


Remove parentheses.
\[\imath v\times 6128+582=Addthefollow\imath ng\times 85+-96\]
Regroup terms.
\[6128\imath v+582=Addthefollow\imath ng\times 85-96\]
Use Product Rule: \({x}^{a}{x}^{b}={x}^{a+b}\).
\[6128\imath v+582=Addthef{o}^{2}{l}^{2}w\imath ng\times 85-96\]
Regroup terms.
\[6128\imath v+582=85Ade\imath dthf{o}^{2}{l}^{2}wng-96\]
Regroup terms.
\[582+6128\imath v=85Ade\imath dthf{o}^{2}{l}^{2}wng-96\]
Regroup terms.
\[582+6128\imath v=-96+85Ade\imath dthf{o}^{2}{l}^{2}wng\]
Subtract \(582\) from both sides.
\[6128\imath v=-96+85Ade\imath dthf{o}^{2}{l}^{2}wng-582\]
Simplify  \(-96+85Ade\imath dthf{o}^{2}{l}^{2}wng-582\)  to  \(-678+85Ade\imath dthf{o}^{2}{l}^{2}wng\).
\[6128\imath v=-678+85Ade\imath dthf{o}^{2}{l}^{2}wng\]
Divide both sides by \(6128\).
\[\imath v=\frac{-678+85Ade\imath dthf{o}^{2}{l}^{2}wng}{6128}\]
Divide both sides by \(\imath \).
\[v=\frac{\frac{-678+85Ade\imath dthf{o}^{2}{l}^{2}wng}{6128}}{\imath }\]
Simplify  \(\frac{\frac{-678+85Ade\imath dthf{o}^{2}{l}^{2}wng}{6128}}{\imath }\)  to  \(\frac{-678+85Ade\imath dthf{o}^{2}{l}^{2}wng}{6128\imath }\).
\[v=\frac{-678+85Ade\imath dthf{o}^{2}{l}^{2}wng}{6128\imath }\]