$$\left. \begin{array} { l } { 8 x ^ { 2 } + 4 x - 9 , 3 x + 5 - 6 x ^ { 2 } } \\ { 8 - 3 x + 9 x ^ { 2 } } \end{array} \right.$$
$\frac{\left(9x^{2}-3x+8\right)\left(\left(12x-3\right)^{2}-129\right)\left(\left(4x+1\right)^{2}-19\right)}{48}$
$8x^{2}+4x-9,\ 5+3x-6x^{2},\ 9x^{2}-3x+8$
