How to solve 81 72 27248 18 ?

1. Factor the equation (x + 2)(x + 3) = 0. 2. Set each factor equal to zero: x + 2 = 0 and x + 3 = 0. 3. Solve for x: x = -2 and x = -3.

Solve 81 72 27248 18 ? | Equatix

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Question

$$\left[ \begin{array} { l } { 81 } \\ { 27 } & { 9 } \end{array} \right] \quad \left[ \begin{array} { l } { 64 } \\ { 24 } \end{array} \right]$$

Evaluate

$\left(\begin{matrix}5184\\1944\end{matrix}\right)$

Steps Using Matrix Multiplication Rule

Matrix multiplication is defined if the number of columns of the first matrix is equal to the number of rows of the second matrix.

$$\left(\begin{matrix}81&0\\27&9\end{matrix}\right)\left(\begin{matrix}64\\24\end{matrix}\right)$$

Multiply each element of the first row of the first matrix by the corresponding element of the first column of the second matrix and then add these products to obtain the element in the first row, first column of the product matrix.

$$\left(\begin{matrix}81\times 64\\\end{matrix}\right)$$

The remaining elements of the product matrix are found in the same way.

$$\left(\begin{matrix}81\times 64\\27\times 64+9\times 24\end{matrix}\right)$$

Simplify each element by multiplying the individual terms.

$$\left(\begin{matrix}5184\\1728+216\end{matrix}\right)$$

Sum each element of the matrix.

$$\left(\begin{matrix}5184\\1944\end{matrix}\right)$$

Show Solution

Transpose Matrix

$\left(\begin{matrix}5184&1944\end{matrix}\right)$